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Correct. There are two separate events but the 2nd event is dependant on the first event happening. So what is the probability of the 1st event AND the 2nd event happening?
You're over-complicating it. We are discounting home and away so it's just a 1 in 15 chance of being paired against any of the teams.
Obviously by teams I mean teams or pairs.
Only reason I said it is because daughters at uni there so and me and her 2 younger twin brothers went down last time we played them on Friday night when we got beat 1-0,and we went and met her for a meal before the game and a few pints before saying our good byes and onto the game.
Not at all. We are calculating the chances of being drawn against each other. We've just done calculation for being first two out of the bag. To do your bookie calculation you are doing a double of 8/1 and 15/1 which for your £1 will give you £120 winnings.
There are 15 teams or pairs who we could possibly be drawn against, so there is a 1 in 15 chance we could be drawn against any of them. 1 in 15 chance we draw Wednesday, 1 in 30 chance it's at Bramall Lane, one in 30 chance it's at Hillsborough. Imagine someone carries a bag with all our potential opponents/pairs written down on screwed up bits of paper, in that bag are the names of our 5th round opponents; there's a 1 in 15 chance it could be any of them.
You are calculating based on us or them being drawn first. So it would be 1 in 15 if that was to happen. But the original question was what are the chances of it happening and the chances are much much more than that because it is a random draw of 8 matches. Only if one of us is drawn first would the chances be 1 in 15.
At this moment in time, the probability of us being drawn against Wednesday on Monday night is 1 in 15.
No they are not. But obviously you don't understand or want to listen! I've tried. I now give up. Do they still do algebra at school these days btw?
Probability is the relevant strand of mathematics. Long time since I was at school. Goodnight.
Yep. Around 4 pages now revolving around probability. Personally, I could not give a minge. Let's wait 48 hours and see.
If Liverpool are drawn out first, the odds remain at 14 to 1. However if a non-Sheffield team is drawn out second, the odds drop to 12/1, because there is now a 1 in 13 chance we'll draw Wednesday.
I’m not sure but I’d guess so.
en.m.wikipedia.org
15/1 actually
I agree re probability. But you are still looking at two specific balls from 16 coming out of the hat successively either 1st and 2nd, or 3rd and 4th, or 5th and 6th or 7th and 8th so the rules as stated are such as described extensively!I’m not sure but I’d guess so.
Algebra - Wikipedia
I’m not sure either what it’s go to do with probabilities.
I don’t want to get into an argument about maths and I haven’t thought about it very deeply but it seems you are trying to calculate the odds for a specific event such as us being the fifth drawn out of the pot and Wednesday being the sixth. That’s not what people are looking at, they’re just looking for probability of us drawing the pigs.
The thing you said about the lottery is correct because you’re calculating the odds of drawing six separate numbers in six separate draws where there is only one winning outcome - the six numbers you predicted would be drawn. The odds when flipping a coin are always evens, the odds that they land in a specific sequence, say heads, heads, tails, heads, tails, tails isn’t 50/50.
I failed my statistics A level many years ago but even I know that you're completely wrong.
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