Sitting next to the same man in successive away games

All advertisments are hidden for logged in members, why not log in/register?

The 4/4,999 isn't right. You halved twice.
The odds are 2/4,999 as you said in the first part, because of there being a seat each side.
I don't know why you've halved again?

What also defies lots of people's logic, is that the odds of it happening again are still 2/4,999 next match. Although it would seem 'impossible'

As Blade83 responded, two people both have two ‘chances’ to sit either side at the next game, so it is 2 x 2.
 

As Blade83 responded, two people both have two ‘chances’ to sit either side at the next game, so it is 2 x 2.
Ok, I get you, because the person on the other side of him, who was at Norwich could have been the one at Barnsley.
As the away games progress this one off part goes away and it just becomes the probability for the individual person.
 
It does because the odds u stated aren't correct that's the probability,
It was a question about the maths, not pedantism of the words, which would make no sense at all, not a factor of 2.
Other posters have understood and explained my question, thanks.
 
Ok, I get you, because the person on the other side of him, who was at Norwich could have been the one at Barnsley.
As the away games progress this one off part goes away and it just becomes the probability for the individual person.

Exactly. The chance of that same person being next to Silent at the next (third in a row) away game is now 2 divided by however many seats we get (minus Silent's seat), because only one fan now has the possibility of being in the sequence. After just one game, two fans have the possibility of staying in the sequence.
 
Going off at a slight tangent, the Blade who sat behind us on John Street for several years, was sitting three seats away at the SCG for the new year test several years ago. Capacity 48,000. Didn't even know he liked cricket.




Yes I did. Thought that would make the story slightly more interesting.😂
 
We sold 2,022 tickets for Norwich and 5,000 for Barnsley. Assuming everyone who bought one attended:

Chances of person x sitting next to person y, with two seats available for person x are:
2 in 2,021 for Norwich = 1 in 1010.5 = a
2 in 4,999 for Barnsley = 1 in 2499.5 = b

Probability of both a and b being achieved = a*b = 1010.5 * 2499.5 = 1 in 2,525,744.75

Edited for simplicity
 
Last edited:
We sold 2,022 tickets for Norwich and 5,000 for Barnsley. Assuming everyone who bought one attended:

Chances of person x sitting next to person y, with two seats available for person x are:
2 in 2,021 for Norwich = 1 in 1010.5 = a
2 in 4,999 for Barnsley = 1 in 2499.5 = b

Probability of both a and b being achieved = a*b = 1010.5 * 2499.5 = 1 in 2,525,744.75

Edited for simplicity

That's not correct. That's the probability for a specific person (i.e. someone identified BEFORE the Norwich game) sitting next to him at both matches.

Turning up to Norwich, it is pretty much already guaranteed that two people will be sat next to Silent. That's already a given. After that, we only need to work out the probabilities for Barnsley.
 
That's not correct. That's the probability for a specific person (i.e. someone identified BEFORE the Norwich game) sitting next to him at both matches.

Turning up to Norwich, it is pretty much already guaranteed that two people will be sat next to Silent. That's already a given. After that, we only need to work out the probabilities for Barnsley.
Ah yes, correct 👍🏻

So when the teachers always said, read the question and take a minute to think before diving in to answering, they were right? 🤣
 
This one will weird you out. I went to USA in 1991, on the flight back to Gatwick I was sat next to a fella who had a very distinctive face. 2 years later I went to a game and sat on the Kop. 2 seats down was the bloke on the plane. I asked him if he was on a flight to Gatwick from Florida in June 1991, he laughed, said yes, then said 'how the hell do you know that!" I didnt tell him it was because he looked like the bad guy from the film Ghost 🤣🤣
 
None of the answers are quite right. Two people (not one) were presumably sat next to Silent at Norwich.

For each person, assuming that everyone at Norwich also went to Barnsley, the odds are 2 / 4,999 that they would be sat in one of the seats either side of Silent Blade. So, the chance of at least one person being sat next to Silent at both games are 4 / 4,999 = 0.0008 or 0.08%. If you prefer odd, 1,995 to 4.

In reality, it's more complex because we don't know how many people attended BOTH matches (if they were completely different sets of people apart from Silent, the chance would be zero, of course). It would also be made a bit more complex by seating arrangements, how they sell blocks of tickets, etc. For instance, if they tend to put 'single ticket' people together, the odds would increase / decrease accordingly.

Let's not open the can of worms again though.
Nobody likes a smart arse.
 
We went to a run of away games, and had a local MP who’s tall enough to block out the sun, sat in front of us for each one.
 

That's not correct. That's the probability for a specific person (i.e. someone identified BEFORE the Norwich game) sitting next to him at both matches.

Turning up to Norwich, it is pretty much already guaranteed that two people will be sat next to Silent. That's already a given. After that, we only need to work out the probabilities for Barnsley.
I think you’d need to factor in the unknown probability of the likelihood that a fan who went to Norwich also went to Barnsley. There must be hundreds who didn’t, decreasing the likelihood of sitting next to the same person at both games.
 
I think you’d need to factor in the unknown probability of the likelihood that a fan who went to Norwich also went to Barnsley. There must be hundreds who didn’t, decreasing the likelihood of sitting next to the same person at both games.

Yep, that was covered in a previous post…

In reality, it's more complex because we don't know how many people attended BOTH matches (if they were completely different sets of people apart from Silent, the chance would be zero, of course). It would also be made a bit more complex by seating arrangements, how they sell blocks of tickets, etc. For instance, if they tend to put 'single ticket' people together, the odds would increase / decrease accordingly.
 

All advertisments are hidden for logged in members, why not log in/register?

All advertisments are hidden for logged in members, why not log in/register?

Back
Top Bottom