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Actually I was wrong earlier. There are fifteen teams or pairs of teams that we could possibly draw. We have an equal probability of playing any of them, so it's one in 15, or 14/1.And I'm telling you your wrong. Its only a 1 in 15 chance if either of us is the first ball out of the bag (as it used to be drawn).
But only if we are first out of the hat.Actually I was wrong earlier. There are fifteen teams or pairs of teams that we could possibly draw. We have an equal probability of playing any of them, so it's one in 15, or 14/1.
The odds before any balls have been drawn (i.e right now) are 15/1. These odds would then shorten after each successive pair of balls have been drawn out, if neither team has been drawn out.And I'm telling you your wrong. Its only a 1 in 15 chance if either of us is the first ball out of the bag (as it used to be drawn).
I was wrong actually. Its much greater than 1 in 48 but I can't be arsed to work it out.Actually I was wrong earlier. There are fifteen teams or pairs of teams that we could possibly draw. We have an equal probability of playing any of them, so it's one in 15, or 14/1.
Doesn't matter whether our ball is drawn out first, second or seventh. Before a ball is drawn, the chances of us drawing a particular club or pair of clubs is one in fifteen.I was wrong actually. Its much greater than 1 in 48 but I can't be arsed to work it out.
Basically there are 16 balls in the bag. We therefore have a 1 in 16 chance of coming out first. There is then a 1 in 15 chance of the pigs coming out second. If neither drawn it then becomes 1 in 14 of one of us next and so on. Therefore the odds of us both coming out against each other are much much greater.
It's one in fifteen, so it's actually 14 to one (contrary to my earlier post).The odds before any balls have been drawn (i.e right now) are 15/1. These odds would then shorten after each successive pair of balls have been drawn out, if neither team has been drawn out.
Did you do algebra at school? The probability of such an event happening is based on the outcome of the first event. So the chances of us being first two out of the bag are 1/16 x 1/15 = 2/240 or 1/120. You then add to the next two, ie 1/14x1/13 and so on to reach the probability of the event happening when dependant on the first event. How do you think bookies make their money?!!Doesn't matter whether our ball is drawn out first, second or seventh. Before a ball is drawn, the chances of us drawing a particular club or pair of clubs is one in fifteen.
So what are the chances ?Did you do algebra at school? The probability of such an event happening is based on the outcome of the first event. So the chances of us being first two out of the bag are 1/16 x 1/15 = 2/240 or 1/120. You then add to the next two, ie 1/14x1/13 and so on to reach the probability of the event happening when dependant on the first event. How do you think bookies make their money?!!
The bookies make their money by giving odds that are not mathematically accurate. i.e. They factor in a profit margin.Did you do algebra at school? The probability of such an event happening is based on the outcome of the first event. So the chances of us being first two out of the bag are 1/16 x 1/15 = 2/240 or 1/120. You then add to the next two, ie 1/14x1/13 and so on to reach the probability of the event happening when dependant on the first event. How do you think bookies make their money?!!
Yeah, that's right.It's one in fifteen, so it's actually 14 to one (contrary to my earlier post).
Can't be arsed to work it out. I was knocking out the memory cells to remember the formula. I used to support a bookmaker in my job and one of their guys once explained it to me. They use similar algarithms to how quickly you can place a bet based on your previous betting history.So what are the chances ?
Nope.Yeah, that's right.
You say the odds of us being drawn together are "much greater than 1 in 48". How can that possibly be right when there are only 15 other teams in the hat? Just think about it ….Nope.
Because you are reliant on one of us being drawn first and then the other being drawn immediately afterwards. There are two events but the second one is reliant on the first. So as I explained the probability of us being droawn first is 1 in 16. The probability of Wednesday being drawn second is 1 in 15. The 2nd event is dependant on the 1st event so the probability of us being drawn first two out of the hat is therefore 1 in 120. If this event didn't happen you would have similar probabilities until just 2 balls left in the bag. You add all these probabilities together and you get the chances of us being drawn against each other. If I had laptop on would do a spreadsheet to show you.You say the odds of us being drawn together are "much greater than 1 in 48". How can that possibly be right when there are only 15 other teams in the hat? Just think about it ….
Did you do algebra at school? The probability of such an event happening is based on the outcome of the first event. So the chances of us being first two out of the bag are 1/16 x 1/15 = 2/240 or 1/120. You then add to the next two, ie 1/14x1/13 and so on to reach the probability of the event happening when dependant on the first event. How do you think bookies make their money?!!
That is true. So it become 1/8 x 1/15 so 1/60. The bookies will give you 40/1 on us being first two out. Years since I did algebra! Can you do the calculation on us being drawn together?You’re nearly right Steve except it’s half of what you said here because the order that we are drawn doesn’t matter. Your odds here are for us to be drawn against them at home. There are equal odds for us at the Sty - ie fist ball out can be us or them 1/8. It’s nCr rather than nPr to a statistician.
That is true. So it become 1/8 x 1/15 so 1/60. The bookies will give you 40/1 on us being first two out. Years since I did algebra! Can you do the calculation on us being drawn together?
Its late!You’re getting there, stats is right now but your maths is wrong! 1/16x1/15 is 1/240 and 1/8x1/15 is 1/120!
It's 1 in 14 - apart from us, there are 15 other teams/balls in the hat and we have to be drawn against one of them!That is true. So it become 1/8 x 1/15 so 1/60. The bookies will give you 40/1 on us being first two out. Years since I did algebra! Can you do the calculation on us being drawn together?
Edit - we do want a home draw!
ucandomagic - Martin over to you. I tried!It's 1 in 14 - apart from us, there are 15 other teams/balls in the hat and we have to be drawn against one of them!
1 in 15, or 14/1.It's 1 in 14 - apart from us, there are 15 other teams/balls in the hat and we have to be drawn against one of them!
It's not 1 in 14, it is of course 1 in 15, or 14/1ucandomagic - Martin over to you. I tried!
Ok lets do this one step at a time. What are the chances of us or pigs being drawn first?It's not 1 in 14, it is of course 1 in 15, or 14/1
2 in 16, or 1 in 8, so 7/1.Ok lets do this one step at a time. What are the chances of us or pigs being drawn first?
So given one of us has been drawn first what are the chances of the other one of us being drawn second?2 in 16, or 1 in 8, so 7/1.
Hope not.I'm going to say Leicester away......again!!!⚔
There are 15 possible teams/pairs who we or they could be drawn against so 1 in 15, or 14 to one.So given one of us has been drawn first what are the chances of the other one of us being drawn second?
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