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We have been drawn at home for all six of the League Cup matches we have played since Chris Wilder became manager (including Sunderland). What are the chances of this happening?
It was my quiz question of the day which KiwiBlade answered correctly. I think so anyway, maths was never my strong pointI’d say the odds of a home tie are about 50/50?
So now all you need to do is work out the odds of 6 consecutive home ties.
I’ve done the hard part for you, so all you need to do is finish off the calculation. You can use your calculator, but I want it in for Monday morning and DON’T forget to show your working out![]()
It also means that the odds of being at home for the next match are tiny. Scientific fact![]()
How can they be? After already coming up six times, it's one in 128 . I've put £100 on skybet for us to be Away, I got Evens. Easy money.The odds of being drawn at home for the next match are 1 in 2.
We have been drawn at home for all six of the League Cup matches we have played since Chris Wilder became manager (including Sunderland). What are the chances of this happening?
Just for the geeks out there why don’t you work out the odds of our ball being picked at the point it was from a bag of 32 say or however many were in when we were drawn then of it being home as well?
Enjoy I’ll be in the corner having a pint
And for betting purposes even money 1/1.The odds of being drawn at home for the next match are 1 in 2.
Odds are 1 in 64
But that changes every time balls are pulled out and it’s not usWell, there are 32 balls, so it's a 1/32 chance of us being pulled out in any position ( we happened to be 9th out of the hat based on the website). If we assume that we don't know that every odd number selection will be at home (which ofcourse it will) then there is a 1/2 chance of us being at home also.
Therefore, the chance of being out 9th in the hat and then at home would be 1/2 x 1/32, which is 1/64.
You're welcome.
Aaahh, but what about when they do that, 'give them a good swirl' thing half way through?Well, there are 32 balls, so it's a 1/32 chance of us being pulled out in any position ( we happened to be 9th out of the hat based on the website). If we assume that we don't know that every odd number selection will be at home (which ofcourse it will) then there is a 1/2 chance of us being at home also.
Therefore, the chance of being out 9th in the hat and then at home would be 1/2 x 1/32, which is 1/64.
You're welcome.
The chances of a home draw in any round are not exactly evens.....
I'm guessing you didn't go for the third degree because it would have been too torturous?Did I mention I've got two Degrees in Statistics?
Drawing balls from a bag is not truly random, only quasi random. The chances of a home draw in any round are not exactly evens.....
Sorry to disappoint
The "balls" will not be uniformly spherical, or the same weight. The fact that different numbers are carved into them will impact on weight & sphericalicity (made up word). It's negligible, but not exactly random. Go to extremes - one is a pea, one a golf ball, one a tennis ball, one a football, one a medicine ball & one is the moon. No way is that draw random....Just when I've got my head round Monty Hall you come up with this.
Go on then, why?
You gonna need a big there fella.The "balls" will not be uniformly spherical, or the same weight. The fact that different numbers are carved into them will impact on weight & sphericalicity (made up word). It's negligible, but not exactly random. Go to extremes - one is a pea, one a golf ball, one a tennis ball, one a football, one a medicine ball & one is the moon. No way is that draw random....
Yet you quote three statistical theorem in your reply.....I'm guessing you didn't go for the third degree because it would have been too torturous?![]()
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